hard · SAT Math
Two branch offices, each with 20 employees, recorded one-way commute times (in minutes) in histograms with the same five intervals. Bar height is the frequency (number of employees) in each interval. Office A — Commute time | Number of employees 0–9 | 2 10–19 | 4 20–29 | 9 30–39 | 4 40–49 | 1 (Total = 20) Office B — Commute time | Number of employees 0–9 | 4 10–19 | 4 20–29 | 4 30–39 | 4 40–49 | 4 (Total = 20) Based on these histograms, which office's commute times have the greater spread?
- It cannot be determined which office has greater spread, since the histograms don't give each employee's exact commute time.
- Office B has the greater spread, because its employees are distributed evenly across all five intervals rather than clustered near the middle.
- Office A has the greater spread, because its tallest bar (9 employees, in the 20–29 interval) is taller than any bar in Office B's histogram.
- The two offices have equal spread, since both sets of bars span the same five 10-minute intervals, from 0 to 49 minutes.
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