hard · SAT Math

Two branch offices, each with 20 employees, recorded one-way commute times (in minutes) in histograms with the same five intervals. Bar height is the frequency (number of employees) in each interval. Office A — Commute time | Number of employees 0–9 | 2 10–19 | 4 20–29 | 9 30–39 | 4 40–49 | 1 (Total = 20) Office B — Commute time | Number of employees 0–9 | 4 10–19 | 4 20–29 | 4 30–39 | 4 40–49 | 4 (Total = 20) Based on these histograms, which office's commute times have the greater spread?

1. It cannot be determined which office has greater spread, since the histograms don't give each employee's exact commute time.
2. Office B has the greater spread, because its employees are distributed evenly across all five intervals rather than clustered near the middle.
3. Office A has the greater spread, because its tallest bar (9 employees, in the 20–29 interval) is taller than any bar in Office B's histogram.
4. The two offices have equal spread, since both sets of bars span the same five 10-minute intervals, from 0 to 49 minutes.

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