medium · MCAT chem-phys
On a balanced seesaw, a child with a mass of 25 kg sits 2.4 m from the central pivot.
At what distance from the pivot must a second child with a mass of 40 kg sit to maintain rotational equilibrium?
- 3.8 m
- 1.5 m
- 2.0 m
- 0.66 m
Sign up free to see the explanation and track your rank →
More MCAT chem-phys practice
- An infrared (IR) spectrum of an unknown organic compound sho… — Which functional group is
- What is the molar mass of Calcium Carbonate (CaCO_3)? (Atomic masses: Ca = 40, C = 12, O =
- How many moles of NH_3 are theoretically produced?
- What is the correct coefficient for O_2?
- What term describes the molecule with internal symmetry despite having chiral centers?
- Which mechanism is occurring?
- Which reactant is the limiting reagent?
- Which term describes the final state where no net heat flow occurs?